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SubstDirect

9/6/2016

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High School Number Sense Lesson 33: Substitution (Direct)

     Direct substitution questions appeared more times than there were tests this year: 22 times, on average at question # 33.  They look different from functions but operate in the same way.

Number Dojo Level: 139

     For these question types, you will be given one or more variables and their equivalents, and a polynomial.  You will be asked to find the value of the polynomial.  A simple version is this:
  • Let x = -5.  Find 4 + 3x. ___
To solve these, simply plug the given values into the polynomial and perform the order of operations (OrderOfOper) to find your answer.  So:
  • 4 + 3x = 4 + 3(-5) = 4 + (-15) = -11

For many of these questions, it will save you lots of time if you know how to factor polynomials.  To learn how to do this, see https://www.khanacademy.org/math/algebra/polynomial-factorization.

Example 1: Let x = -2.  Find 3 - 4x. ___
  • 3 - 4x = 3 - 4(-2) = 3 + 8 = 11
​
Example 2: Let x = -4.  Find 3x - 2. ___
  • 3x - 2 = 3(-4) - 2 = -12 - 2 = -14

Example 3:
If x = 2 and y = 5, then 4x2 + 4xy + y2 = ___
1. This polynomial can be factored to become (2x + y)2.
2. Substitute 2 for x and 5 for y: (2x + y)2 = [2(2) + 5]2 = (4 + 5)2 = 92 = 81.
Example 4:
If x = 5 and y = -1, then x2 + 2xy + y2 = ___
1. This polynomial can be factored to become (x + y)2.
2. Substitute 5 for x and -1 for y: (x + y)2 = [5 + (-1)]2 = (5 - 1)2 = 42 = 16.
Example 5:
If x = 5 and y = 3, then 9x2 - 6xy + y2 = ___
1. This polynomial can be factored to become (3x - y)2.
2. Substitute 5 for x and 3 for y: (3x - y)2 = [3(5) - 3]2 = (15 - 3)2 = 122 = 144.
Example 6:
If x = 5 and y = 2, then (x - y)(x2 + 2xy + y2) equals ___
1. As seen above, (x2 + 2xy + y2) can be factored as (x + y)2. So now we have (x - y)(x + y)2.
2. Substitute 5 for x and 2 for y: (x - y)(x + y)2 = (5 - 2)(5 + 2)2 = (3)(7)2 = 3(49) = 147.
Here's a free worksheet to help you practice SubstDirect:
substdirect.pdf
File Size: 239 kb
File Type: pdf
Download File

Up Next for High School: BaseNtoBase10
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